A vessel is filled with liquid, 3 parts of which are water and 5 parts of syrup. How much of the mixture must be drawn off and replaced with water so that the mixture may be half water and half syrup?
Explanation:
Suppose the vessel initially contains 8 litres of liquid.
Let x litres of this liquid be replaced with water.
Quantity of water in new mixture = (3−3x/8+x) litres.
Quantity of syrup in new mixture = (5−5x/8) litres.
(3−3x/8+x)=(5−5x/8)
=> 5x + 24 = 40 - 5x
=> 10x = 16 => x = 8/5
So, part of the mixture replaced = (85×18) = 1/5.
hence, option 2 is the correct answer.
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By: Amit Kumar