Problems on trains

Quantitative Aptitude (SBI-CL)

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A train 125 m long passes a man, running at 5 kmph in the same direction in which the train is going, in 10 seconds. The speed of the train is?

35 km/hr

50 km/hr

48 km/hr

55 km/hr

Explanation:

Let speed be S
Relative speed = total lengths/time [ in this case man length is neglible compare to train so neglected] (S – 5) x 5/18 = 125 /10
S- 5 = (125/10)x(18/5)
S-5 = 45
S=50 km/hr

By: Sandeep Dubey

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