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Consider the following redox reaction :

2Cu₂O (s) + Cu₂S(s) → 6Cu (s) + SO₂ (g)

Identify the species among the following acting as oxidant and reductant, respectively :

This questions was previously asked in

CAPF 2023 Paper-1

Cu(I) and S of Cu₂S

(I) and S of Cu₂S

Cu(I) and S of Cu

Cu(I) and Cu₂S

Cu(I) and S of Cu₂S.

Let us assign oxidation number to each of the species in the reaction under examination.
This results into: + 1 – 2 + 1 – 2 0 + 4 – 2

2 C u 2 O ( s ) + C u 2 S ( s ) → 6 C u ( s ) + S O 2

We therefore, conclude that in this reaction copper is reduced from + 1 state to zero oxidation state and sulphur is oxidised from – 2 state to + 4 state.
The above reaction is thus a redox reaction.
Further, C u 2 O helps sulphur in C u 2 S to increase its oxidation number, therefore, C u ( I ) is an oxidant; and sulphur of C u 2 S helps copper both in C u 2 S itself and C u 2 O to decrease its oxidation number; therefore, sulphur of C u 2 S is reductant.