Multiple Choice Questions on From a Circular metal plate of radius 7 cm and thickness 0 bull 16 mm a sector is cut off containing........... for CDS Exam Preparation

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    From a Circular metal plate of radius 7 cm and thickness 0•16 mm, a sector is cut off containing an angle 150°. The remaining piece is moulded into a spherical bead of radius r. What is the value of r in cm ?

    This questions was previously asked in
    2024 CDS -1 MATH

    0.35

    Incorrect Answer

    0.7

    Correct Answer

    1.05

    Incorrect Answer

    1.4

    Incorrect Answer
    Explanation:

    Correct option 2: 0.7 cm

    Given:

    Radius of circular plate (R) = 7 cm

    Thickness of plate (h) = 0.16 mm = 0.016 cm

    Angle of the sector (θ) = 150°

    Concept:

    The volume of the remaining piece after cutting the sector is equal to the volume of the spherical bead formed. Formula used:

    Volume of the sector of a cylinder = ( θ/360) π R2h

    Volume of the sphere = (4/3) π r3

    Solution:

    Volume of the sector cut off:

    => (150/360) × π x(7)2 × 0.016

    => (5/12) × π x 49 × 0.016

    => 1.026 cm3

    Volume of the remaining piece:

    => Total volume of the plate - Volume of the sector cut off

    => π x R2xh-1.026

    =>? × 49 × 0.016 - 1.026

    => 3.14 × 0.784 - 1.026

    =>2.46176-1.026

    => 1.43576 cm3

    Volume of the spherical bead: => (4/3)π r3= 1.43576

    => r3 = (1.43576 × 3)/(4xπ)

    => r3 = 0.3427 cm3 = 0.343 cm3

    => r = 3√0.343

    => r = 0.7 cm

    .. The value of r is 0.7 cm.


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