In a certain year, the population of a city was 18000. If in the next year, the population of males increased by 5% and that of females increased by 7%, and the total population increased to 19200, then what was the ratio of the populations of males and females in that given year?
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Explanation:
- Initially, let the population of males be \( M \) and that of females be \( F \).
- Total initial population is given as \( M + F = 18000 \).
- In the next year, male population becomes \( M \times 1.05 \) and female population becomes \( F \times 1.07 \).
- New total population is \( M \times 1.05 + F \times 1.07 = 19200 \).
Now, let's solve for \( M \) and \( F \).
\[
1.05M + 1.07F = 19200
\]
\[
M + F = 18000
\]
- By solving these equations simultaneously, we get:
- Subtracting the first equation from 1.05 times the second equation:
\[
1.05(M + F) - (1.05M + 1.07F) = 1.05 \times 18000 - 19200
\]
- Simplifying:
\[
1.05M + 1.05F - 1.05M - 1.07F = 18900 - 19200
\]
\[
-0.02F = -300
\]
\[
F = 15000
\]
- Using \( M + F = 18000 \):
\[
M + 15000 = 18000
\]
\[
M = 3000
\]
- Therefore, the ratio \( M:F = 3000:15000 = 1:5 \).
- Answer: 1:5
By: Parvesh Mehta ProfileResourcesReport error