Directions: Read the following information carefully and answer the questions that follow:
Eight persons A, B, C, D, E, F, G, and H were born in different years viz. 1963, 1967, 1973, 1979, 1984, 1989, 1992, and 1999 but not necessarily in the same order. It is assumed that all of them were born on the same date of different years. All the age calculations are done taking the base year as 2020. H was born immediately before G. There is a gap of six years between the years in which C and D were born. D is younger than C. The sum of ages of E and F is 57. The age difference between A and B is four years. E is younger than H. A is older than B.
Who among the following was born in 1989?
This questions was previously asked in
IBPS Clerk Prelims
Explanation:
- H was born immediately before G, so H is one year older than G.
- Gap of six years between C and D, and D is younger than C.
- Sum of ages of E and F is 57. Thus, if E is 27 (born in 1993), F must be 30 (born in 1990).
- Age difference between A and B is four years, with A older than B.
- Base year is 2020, which means finding out the birth years.
- H is older than E; E isn’t the youngest.
Let’s arrange based on the above:
- 1963: (57 years) – C
- 1967: (53 years) – D (younger than C, 6 year gap)
- 1973: (47 years) – A
- 1979: (41 years) – B (A is older by 4 years)
- 1984: (36 years) – Not used yet
- 1989: (31 years) – Possible for F but E+F doesn’t add up to 57
- 1992: (28 years) – Possible for G, H one year elder so 1991 or 1990 possible
- 1999: (21 years) – E, younger than H
Therefore, H is born in 1989.
The answer is: Option 4: H
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By: Parvesh Mehta