A person invested a sum of Rs10,500 at x% per annum atsimple interest and a sum of Rs13,500 at (x + 2)% p.a. at simpleinterest. If the
total interest earned on both the investmentsfor 3 years is Rs7,650, then the rate of interest on the first investment is:
This questions was previously asked in
SSC CPO 11th Dec 2019 Shift-2
Explanation:
To solve the problem, let's calculate:
- First investment: Rs 10,500 at x% for 3 years yields interest = 3 * 10500 * (x/100).
- Second investment: Rs 13,500 at (x + 2)% for 3 years yields interest = 3 * 13500 * ((x + 2)/100).
- Total interest from both = 7650.
For the calculations:
1. The equation becomes: 315x + 405(x + 2) = 7650.
2. Simplifying, we get: 720x + 810 = 7650.
3. Further simplification gives: 720x = 6840.
4. Solving for x, we find x = 9.
So, the rate of interest for the first investment is 9%.
- Option 1 is 8% ?
- Option 2 is 8.5% ?
- Option 3 is 9%
- Option 4 is 9.5% ?
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