Time & distance

Quantitative Aptitude (MTS)

Title

45:30

8 of 24 completed

5 of 15 completed

38 of 100 completed

8 of 20 completed

Indian Economy - Understanding the basics of Indian economic system

A thief escapes from a police sta tion at 8:00 a.111. on a cycle at a speed of 50 km/h. A policeman sta11s chasing the thief on

a motorbike at 9:30 a.111. at the speed of 65 km/h. At what distance from the police station will the policeman catch up with

the thief?

This questions was previously asked in

SSC MTS 5th July 2022 Shift-3

335 km

310 km

325 km

300 km

- The thief leaves at 8:00 a.m. going at 50 km/h. By 9:30 a.m., he has been cycling for 1.5 hours.

- Distance covered by the thief by 9:30 a.m. = 50 km/h * 1.5 h = 75 km.

- The policeman starts chasing at 9:30 a.m., traveling at 65 km/h.

- Relative speed between the policeman and the thief = 65 km/h - 50 km/h = 15 km/h.

- Time needed for the policeman to catch up = Distance difference / Relative speed = 75 km / 15 km/h = 5 hours.

- Distance the policeman covers in those 5 hours = 65 km/h * 5 h = 325 km.

The correct answer is Option: 3 - 325 km