Quadrilateral ABCD circumscribes circle. If AB = 8 cm, BC = 7 cm and CD = 6 cm,then the length of AD is:
This questions was previously asked in
SSC CGL 3rd March 2020 Shift-2
Explanation:
- For a quadrilateral to circumscribe a circle, the sum of opposite sides must be equal. This is known as the Pitot theorem.
- According to Pitot's theorem: \( AB + CD = AD + BC \).
- You have given:
- \( AB = 8 \) cm
- \( BC = 7 \) cm
- \( CD = 6 \) cm
- Apply the theorem:
- \( 8 + 6 = AD + 7 \)
- Simplify:
- \( 14 = AD + 7 \)
- Hence, \( AD = 7 \) cm.
- Option:1, 6 cm
- Option:2, 7.5 cm
- Option:3, 7 cm
- Option:4, 6.8 cm
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By: santosh