Multiple Choice Questions on The present age of a father is three times that of his elder son Four years hence the age of the fat........... for SSC CGL Exam Preparation

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    The present age of a father is three times that of his elder son. Four years hence, the age of the father will be four times that of

    his younger son. If the difference between the present

    ages of the elder and younger child is 6 years, what is the present age of the father?

    This questions was previously asked in
    SSC CGL 16th August 2021 Shift-2

    36 years

    Correct Answer

    32 years

    Incorrect Answer

    38 years

    Incorrect Answer

    42 years

    Incorrect Answer
    Explanation:

    - Let's denote the present age of the father as F, the elder son's age as E, and the younger son's age as Y.

    - The father's age is three times the elder son's: \( F = 3E \).

    - Four years from now, the father's age will be four times the younger son's: \( F + 4 = 4(Y + 4) \).

    - The difference between the elder and younger son's age is 6 years: \( E = Y + 6 \).

    - Using the equations, we can substitute and solve:

    - From \( F = 3E \) and using \( E = Y + 6 \), we substitute to get \( F = 3(Y + 6) = 3Y + 18 \).

    - Substituting into the equation \( F + 4 = 4(Y + 4) \), we have \( 3Y + 18 + 4 = 4Y + 16 \).

    - Simplifying, we get \( 22 = Y + 16 \), meaning \( Y = 6 \).

    - Substituting Y back, \( E = 12 \) (since \( E = Y + 6 \)), and so \( F = 36 \) (since \( F = 3E = 36 \)).

    - Answer: Option 1, 36 years, is the correct answer.


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