The present age of a father is three times that of his elder son. Four years hence, the age of the father will be four times that of
his younger son. If the difference between the present
ages of the elder and younger child is 6 years, what is the present age of the father?
This questions was previously asked in
SSC CGL 16th August 2021 Shift-2
32 years
Incorrect Answer38 years
Incorrect Answer42 years
Incorrect AnswerExplanation:
- Let's denote the present age of the father as F, the elder son's age as E, and the younger son's age as Y.
- The father's age is three times the elder son's: \( F = 3E \).
- Four years from now, the father's age will be four times the younger son's: \( F + 4 = 4(Y + 4) \).
- The difference between the elder and younger son's age is 6 years: \( E = Y + 6 \).
- Using the equations, we can substitute and solve:
- From \( F = 3E \) and using \( E = Y + 6 \), we substitute to get \( F = 3(Y + 6) = 3Y + 18 \).
- Substituting into the equation \( F + 4 = 4(Y + 4) \), we have \( 3Y + 18 + 4 = 4Y + 16 \).
- Simplifying, we get \( 22 = Y + 16 \), meaning \( Y = 6 \).
- Substituting Y back, \( E = 12 \) (since \( E = Y + 6 \)), and so \( F = 36 \) (since \( F = 3E = 36 \)).
- Answer: Option 1, 36 years, is the correct answer.