Time & distance

Quantitative Aptitude (CPO)

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A thief is spotted by a policeman from a distance of 250m. When the policeman starts the chase, the thief also starts running.

Assuming that the speed of the thief is 10 km/h and that of the policeman is 12 km/h, how far would the thief have run before

he is caught?

This questions was previously asked in

SSC CPO 9th Nov 2022 Shift 1

4 km

1.25 km

3 km

2 km

- The scenario involves a policeman chasing a thief, both starting at the same moment.

- The distance between them initially is 250 meters.

- The thief runs at a speed of 10 km/h.

- The policeman runs faster, at 12 km/h.

- We need to find out how far the thief runs before being caught.

- The relative speed between the policeman and the thief is 2 km/h (12 km/h - 10 km/h).

- To close the 250-meter gap at a relative speed of 2 km/h, the time taken is 0.125 hours (since 250 meters is 0.25 km, and time = distance/speed).

- During this time, the thief runs a distance of 1.25 km (at 10 km/h for 0.125 hours).

Correct Answer: Option 2 - 1.25 km