A batsman in his 11th inning scores 88 runs, thereby increasing his average score by 4. What is his average after the 11th
innings?
This questions was previously asked in
SSC CHSL 6th June 2022 Shift-2
Explanation:
- The batsman has played 10 innings before the 11th. Let his average before the 11th inning be \( x \).
- Total runs scored in 10 innings = \( 10x \).
- After scoring 88 runs in the 11th inning, his new total runs = \( 10x + 88 \).
- New average after 11th inning is \( x + 4 \).
- Therefore, \(\frac{10x + 88}{11} = x + 4\).
- Solving gives: \( 10x + 88 = 11x + 44 \).
- Equation simplifies to: \( x = 44 \).
- New average: \( 44 + 4 = 48 \).
- Option 3: 48 is correct.
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