Time & distance

Quantitative Aptitude (CHSL)

Title

45:30

8 of 24 completed

5 of 15 completed

38 of 100 completed

8 of 20 completed

Indian Economy - Understanding the basics of Indian economic system

Ramesh drives from his home at a speed of 40 km/h and reaches his college 25 minutes late. The next day he increases his

speed by 10 km/h, yet he is late by 10 minutes. How far is his college from his home?

This questions was previously asked in

SSC CHSL 24th May 2022 Shift-1

50 km

55 km

45 km

60 km

- Ramesh travels at 40 km/h and is 25 minutes late, and the next day at 50 km/h, he is only 10 minutes late.

- Let's denote the actual time Ramesh should take to reach college as \( t \).

- The first day, the time taken is \( \frac{d}{40} = t + \frac{25}{60} \).

- The second day, the time taken is \( \frac{d}{50} = t + \frac{10}{60} \).

- Solving these equations:

\[ \frac{d}{40} - \frac{d}{50} = \frac{25}{60} - \frac{10}{60} \]

\[ \frac{5d}{2000} = \frac{15}{60} \]

\[ d = 50 \, \text{km} \]

- Correct Option: \(\) Option 1: 50 km