In a mixture, ratio of milk and water is 6 : 1. 21 liters of mixture is withdrawn, and 77 liters of water is added to the mixture. If the total quantity of resultant mixture is twice of the quantity of original mixture, what was the amount of milk in original mixture?
Explanation:
Let the quantity of milk and water be 6x and x respectively.
Quantity of milk removed from mixture = 6/7 x 21= 18 litres
Quantity of water removed from mixture =1/7 x21 = 3 litres
According to question,
7x – 21 + 77 = 2 × 7x
⇒ 7x = 56 ⇒ x = 8
Quantity of milk in original mixture = 6 × 8 = 48 litres