Directions (): Answer the questions based on the information given below.
The given line graph shows the sum of the cost price and selling price, and the discount offered on five different articles.
The sum of the discounts offered on all these articles is Rs. 2300.
The cost price of the article ‘F’ is 2.5 times the discount offered on article ‘D’. The sum of the selling price and cost price of article ‘F’ is equal to that of ‘E’. If the discount offered on article ‘F’ is 25% of the sum of the selling price and cost price of article ‘B’, then find the amount by which article ‘F’ is marked up.
Rs. 1080.5
Incorrect Answer Rs. 612.5
Incorrect AnswerExplanation:
Cost price of article ‘F’ = 2.5 × 660 = Rs. 1650
Selling price of article ‘F’ = 3000 – 1650 = Rs. 1350
Discount offered on the article = 0.25 × 3850 = Rs. 962.5
Therefore, marked price of the article = 1350 + 962.5 =Rs. 2312.5
mount by which article ‘F’ is marked up = 2312.5 – 1650 = Rs. 662.5
Common Explanation:
20x + 10x + 22x + 33x + 30x = 2300
Or, 115x = 2300
Or, x = 20
Discount offered (in Rs.)
A => 20x = 400
B => 10x = 200
C => 22x = 440
D => 33x = 660
E => 30x = 600
Let the cost price of the article be Rs. x
Therefore, selling price of the article = Rs. (x + 100)
According to the question,
(x + x + 100) = 5100
Or, 2x = 5000
Or, x = Rs. 2500
Therefore, cost price of the article = Rs. 2500
Selling price of the article = (2500 + 100) = Rs. 2600
Therefore, marked price of the article ‘A’ = (2600 + 400)= Rs. 3000
Amount by which article ‘A’ is marked up = (3000 –2500) = Rs. 500
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By: Munesh Kumari