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Quantitative Aptitude (CDS)

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If P(A?B)=0.8 and P(A?B)=0.3,then P(A')+P(B') equals to?

1.1

0.9

1.2

0.1

Explanation:

Here P(A'?B')=1-P(A?B)

=1-0.8

=0.2

P(A'?B')=1-P(A?B)

=1-0.3

=0.7

As we know that-

P(A'?B')=P(A')+P(B')-P(A'?B')

0.7=P(A') +P(B')-0.2

P(A')+P(B')=0.7+0.2=0.9

By: bhavesh kumar singh

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