Web Notes on Percentage -3 for CAPF (AC) Exam Preparation

Percentage

Quantitative Aptitude( Paper-I )

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    Percentage -3

    Percentage Part-3

    In Continution to the previous notes...

    Expenditure and consumption:

    expenditure = price x quantity 

    case -1 : when expenditure is constant 
    then price and quantity are inversly proportional 
    i.e

    ∝ 1/q

    or 

    q ∝ 1/p 

    case -2 
    when price constant 
    exp. ∝ qunt 
     

    case -3 
    when quantity constant 
    exp. ∝ price  


    Question1 : If the price of milk increased by 25%, by how much per cent must Rahul decrease his consumption, so as his expenditure remains the same.
    Solution: Let the price of milk is 20 Rs/ litre and Rahul consumes 1-litre milk.
    Expenditure of Rahul = price × consumption
    Now the price of milk is increased by 25%, so the new price is (125/100)× 20 = 25 Rs.
    but his expenditure remains the same
    So, new consumption × new price = old price × old consumption
          new consumption × 25 = 20 × old consumption
          new consumption  =(20/25)  × old consumption
          new consumption% = (20/25)× old consumption × 100
          new consumption% = 80% of old consumption
    decrease in consumption = 20 %
    Using above trick:  Given, price % is increased so sign will be (+) and consumption % will decrease.
    Decrease in consumption =(25/125) 
    × 100 = 20%

    or 
                  original : final  
    price -       4        :      5 

    Quantity - 5        :     4
    => (1/5) x 100 % = 20 %  

    Question- 2  : If the price of milk decreased by 25%, by how much percent must Rahul increase his consumption, so as his expenditure remains the same.
    Solution: Let the price of milk is 20 Rs/ litre and Rahul consumes 1-litre milk.
    Expenditure of Rahul = price × consumption
    Now the price of milk is decreased by 25%, so the new price is × 20 = 15 Rs.
    but his expenditure remains the same
    So, new consumption × new price = old price × old consumption
          new consumption × 15 = 20 × old consumption
          new consumption  =  (20/15)× old consumption
          new consumption% = (20/15)× old consumption × 100
          new consumption% = 133(1/3)% of old consumption
         increase in consumption = 33(1/3) %
    Using above trick: given price % is decreased so sign will be (-) and consumption % will increase.
    Increase in consumption = (25/75) x  100 = 33(1/3)%

    OR 

                  original : final  
    price -       4        :      3 

    Quantity - 3        :     4

    (1/3) x 100% = 33 1/3%
     

    Marks based questions

    If the passing marks in an examination is R%. If a candidate scores S marks and fails by F marks,then

    Maximum Marks =       

     \frac{100 \times (S + F)}{R}

    Question 3:A student has to score 30% marks to get through. If he gets 30 marks and fails by 30 marks, then find the maximum marks set for the examination ?
    Solution:

    Maximum Marks=100(30+30)/30=200 Marks

    or

    if student gets 30 marks and fail by 30 marks then passing marks for the student will be 60 
    i.e

    30% of total marks = 60 
    => 1% of total marks = 2 
    100% of total marks = 200 

    Question 4:

    At an examination in which maximum marks are 500. K got 10% less than L, L got 25% more than M and M got 20% less than N. If K got 360 marks what percentage of marks was obtained by N ?

    Solution:

    Let marks obtained by N = x

    M's marks = 0.80x

    L's marks = 1.25 (0.80x)

    K's marks = (0.90) (1.25) (0.80x) = 0.9x

    But 0.9x = 360 ⇒ x = 400

    Percentage of Marks obtained by N

    = 400 x 100/500 = 80%

    or by ratio and proportion 
      K  :   L   :   M    :   N 
     9   : 10       ---      ---

     ---     5   :   4        ---
     ---   ---       4     :    5
    ---------------------------- 

    ----------------------------

     K  :   L   :   M    :   N 
     9     10     10       10
     5       5      4         4
     4       4      4         5 

    FINAL RATIO 
    K      : L      : M      : N

    180 : 200 : 160   : 200

    marks of k = 360 i.e 180 unit = 360 marks 

    200 units ( value of N ) = 200 x 2 = 400 

    Distribution based Question:

    Question 5: Gaurav spends 30% of his monthly income on food articles, 40% of the remaining on conveyance and clothes and saves 50% of the remaining. If his monthly salary is Rs. 18,400, how much money does he save every month ?

    Solution:

    Saving  = 50% of (100 - 40)% of (100 - 30)% of Rs. 18,400

    = Rs. (50/100 * 60/100 * 70/100 * 18400)

    = Rs. 3864.

    or 

    10 : 7 
     5 : 3 
     2 : 1 
    -----------
    100 : 21 
    -----------

    100 unit = 18400 
    1 unit = 184 
    21 unit = 184 x 21 
    3864 rs 

     

    Question 6:   Radha spends 40% of her salary on food, 20% on house rent, 10% on entertainment and 10% on conveyance. If her savings at the end of a month are Rs. 1500, then her salary per month (in Rs.) is ?

    Solution:

    Assume the Total Salary = 100%

    Expenditures:-

    Food = 40%

    House Rent = 20%

    Entertainment = 10%

    Conveyance = 10%

    Total Expenditure = 80%

    Savings = 100% - 80% = 20% ---------> 1500 Rs.

    1% ---------> 1500 Rs./20 = 75 Rs.

    100% ---------> 75 * 100 = 7500 Rs.

     


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