There are 20 couples in a party. Every person greets every other person except his or her spouse. People of the same sex shake hand and those of the opposite sex greet each other with Namaskar. What is the total number of handshakes and namaskars in that party?
Explanation:
There are 20 men and 20 women.
When a man meets a woman, there are two namaskars, whereas when a man meets a man (or a woman) there is only 1 handshake.
Number of handshakes =2×20C2 (men and women ) = 2×20×192 = 380
For number of Namskars Every man does 19 namaskars (to the 20 women excluding his wife) and they respond in the same way.
Number of Namaskars,
=2×(20)(19)
=2×380 =760
Total,
=760+380 = 1140
Hence, option 2 is the correct answer.