Algebra

Quantitative Aptitude (CPO)

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If x = 332, y = 333, z = 335 then the value of x³ + y³ + z³ – 3xyz = ?

1000

9000

7000

65000

Explanation:

? (x³ + y³ + z³ – 3xyz)
= (x + y + z) (x² + y² + z² – xy – yz – zx)
= (x + y + z) × 1/2 [(x – y)² + (y – z)² + (z – x)²]
On putting the values, we get
= 1000 × 1/2 [(332 – 333)² + (333 – 335)² + (335 – 332)²
= 1000 × 1/2 [1 + 4 + 9]
= 7000

By: Amit Kumar

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