Ten years ago, the age of the mother was three times the age of her son. After ten years, the mother’s age will be twice that of his son. Find the ratio of their present ages.
Explanation:
10 years ago, the age of the mother was three times the age of her son. Say, the age of son was x, and the mother's age was 3x.
At present: Mother's age is (3x + 10) and son’s age is (x + 10)
After ten years: Mother's age will be (3x + 10) +10 and son’s age will be (x + 10) + 10. Given that, the mother’s age is twice that of son after ten years.
(3x + 10) +10 = 2 [(x + 10) + 10]
(3x + 20) = 2[x + 20]
Solving the equation, we get x = 20
(3x + 10): (x + 10) = 70: 30 = 7: 3.
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By: bhavesh kumar singh