Solution of y dx-x dy +y2 sin xdx =0 is equal to
y = -x cos x +cx
Incorrect Answerx =y cos x +cy
Correct Answery = x cos x +cx
Incorrect Answerx =-ycos x +cy
Incorrect AnswerExplanation:
To solve the given differential equation \( y \, dx - x \, dy + y^2 \sin x \, dx = 0 \):
- Rearrange: The equation simplifies to \( (y + y^2 \sin x) \, dx - x \, dy = 0 \).
- Integrating factor and derivation lead to the solution:
Option Analysis:
1. \( y = -x \cos x + cx \)
- This suggestion doesn't match the expected solution form.
2. x = y \cos x + cy
- This solution captures the implicit relationship derived. It matches the solution approach.
3. \( y = x \cos x + cx \)
- This also doesn’t align well with integration results.
4. \( x = -y \cos x + cy \)
- This is a variation and does not match derived solution steps.
By: Swaminath Yadav ProfileResourcesReport error