If the volume occupied by one mole of a gas at normal temperature and pressure is 22.4 litres, then the volume occupied by 5.6 grams of nitrogen (Atomic weight = 14) at normal temperature and pressure will be:
2.24 litres
Incorrect Answer4.48 litres
Correct Answer11.2 litres
Incorrect Answer22.4 litres
Incorrect AnswerExplanation:
To find the volume occupied by 5.6 grams of nitrogen at normal temperature and pressure, follow these steps:
- Molecular weight of nitrogen (N2): 14 x 2 = 28 grams/mole.
- Calculate moles of nitrogen: 5.6 grams / 28 grams per mole = 0.2 moles.
- Volume occupied by 1 mole of gas: 22.4 litres (at normal temperature and pressure).
- Volume occupied by 0.2 moles: 0.2 x 22.4 litres = 4.48 litres.
Given the options, the correct answer is:
- Option 1: 2.24 litres – Incorrect, as it’s too low.
- Option 2: 4.48 litres – Correct volume.
- Option 3: 11.2 litres – Too high, equivalent to 0.5 moles of gas.
- Option 4: 22.4 litres – It's for 1 mole, not applicable here.
Option 2: 4.48 litres is correct.
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By: Parvesh Mehta