Two years ago a man was six times as old as his son. In 18 years, he will be twice as old as
his son. What are their present ages of the man and his son?
32 and 7 years
Correct Answer34 and 9 years
Incorrect Answer32 and 13 years
Incorrect Answer34 and 7 years
Incorrect AnswerExplanation:
Let the age of a man two years ago = 6x years
age of his son two years ago = x years
so, present age of man
(6x +2) years
According to the question
6x + 2 + 18 = 2 / x + 2 + 18 = 1
6x - 2x = 40 - 20
4x= 20
x = 5
SO present age of man = 6 x 5 + 2 = 32 years
Present age of son = 5 +2 = 7 years
Hence option 1 is the correct answer.