Time & distance

Quantitative Aptitude ( CCS)

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A dog at point A goes in pursuit of a fox 40 m away. The dog takes a leap of 2 m against 1 m long leaps of fox. If the dog makes two leaps to the fox's three, at what distance from A will the dog catch up with the fox?

100 m

180 m

120 m

160 m

Explanation:

let the fox and dog take 3 leaps and 2 leaps respectively per second.
thus speed of fox = 3*1 m/s = 3 m/s
speed of dog = 2*2 m/s = 4 m/s.
thus relative dist bet fox and dog = 40m
rel speed = 1 m/s
thus time taken to catch = 40 s
At the time interval, fox will travel 3 m/s * 40 s = 120 m from A
thus answer is 120m +40m = 160m

Hence, option 4 is the correct answer.

By: Amit Kumar

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