A train lsquo X rsquo leaves station lsquo A rsquo at 3 p m and reaches station lsquo B rsquo at 4 3...........

Quantitative Aptitiude (CLAT) Time & distance

A train ‘X’ leaves station ‘A’ at 3 p.m and reaches station ‘B’ at 4.30 p.m., while another train ‘Y’ leaves station ‘B’ at 3.00 p.m and reaches station ‘A’ at 4.00 p.m. These two trains cross each other at:

3.30 p.m.

3.20 p.m.

3.40 p.m.

3.36 p.m.

Explanation:

Let the distance between A and B be 60km
Time taken by X to travel from A to B is 1.5 hrs
Time taken by Y to travel from B to A is one hrs
speed = D/T
X = 60/1.5 = 40kmph
Y = 60/1 = 60kmph
60/(40+60) = 60/100 = 0.6
0.6 × 60 = 36min
so trains will meet each other at 3:36 PM