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A, B, C and D have got some money with them. If A gives 8 rupees to B, B will have as much as C has and A will have 3 rupees less than what C has. Also if A takes 6 rupees from C, A will have twice as much money as D. If B and D together have 50 rupees, how much money does A and B have respectively ?
29, 32
27,40
32,29
40,27
Let A has Rs.x , B has Rs.y If A gives Rs.8 to B then A has x-8 , B has y+8 and B becomes equal to C, so let C has Rs.y+8. Also A will have Rs 3 less than C , x-8 = y+8-3 => x - y = 13. -(1)
If A takes Rs.6 from C then A will have x+6 , C will have y+8-6 = y+2 and A becomes twice of D , let D has Rs.z So now , x+6=2z. -(2) B+D = Rs.50 => y+z = 50. -(3)
From eq(2) , z = (x+6)/2. Putting this value of z in eq (3) , we get , y+(x+6)/2 = 50 => 2y+x+6 = 100 => 2y+x = 94. -(4)
On solving eq (1) & (4) , we get y = 27 then , x = 40. Therefore A has Rs. 40 and B has Rs. 27
By: Amit Kumar ProfileResourcesReport error
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