An old woman decided to divide her gold among her daughter and daughters in law She first kept exact...........

Logial Reasoning (CLAT) Arithmetical Reasoning

An old woman decided to divide her gold among her daughter and daughters-in-law. She first kept exactly half of the gold for her daughter. Then she divided the rest of her gold among her daughters-in-law. The eldest one got 26 grams more than the youngest daughter-in-law. The middle one got twice as the youngest one. If the eldest daughter-in-law got 66 grams of gold, how much was received by the daughter?

198 grams

172 grams

186 grams

194 grams

Explanation:

Read the question carefully it says there are few grams of gold with a old women 1st she gave half of the gold to her daughter and the remaining half she distributes among her 3 daughter in laws amount those 3 daughter in-laws the eldest one gets 66 grams,
which is 26 grams more than younger one, then the middle one gets twice the youngest one. now subtract those 66 grams with 26 grams to get the youngest daughter in law share it will be 40 grams,
younger daughter in law got 40 grams the middle daughter in law gets twice then the youngest one,
and it is 40+40=80 grams now add the three daughter in laws share to get,
the old women's daughter share it will be 40+66+80=186grams