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Greatest number which divides 926 and 2313, leaving 2 and 3 remainders, respectively, is
52
54
152
154
Let the number be x. x should divide 926 by leaving a remainder of 2. So that means x will be a factor of 926–2 = 924. Similarly, x should be a factor of 2313–3=2310. Since we want the greatest number which is a factor of both 924 and 2310, we try to find their HCF. x = HCF(924,2310) = 462. 462 is divisible by only 154. Hence, option 4 is the correct answer.
By: Amit Kumar ProfileResourcesReport error
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