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A man has 9 friends: 4 boys and 5 girls. In how many ways can he invite them, if there have to be exactly 3 girls in the invitees?
320
160
80
200
If he invites 3 girls and 4 boys=5c3×4c4=10 ways. 3 girls 3 boys =5c3×4c3=40 ways. 3 girls 2 boys =5c3×4c2=60 ways. 3 girls 1 boy =5c3×4c1=40 ways. 3 girls no boys =5c3 ×4c0=10 ways. =10+40+60+40+10=160 ways.
By: Amit Kumar ProfileResourcesReport error
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