Let x be the greatest number of 4 digits which when divided by 15 20 and 28 leaves in each case the ...........

Quantitative Aptitiude (CLAT) LCM, HCF

Let x be the greatest number of 4 digits, which when divided by 15, 20 and 28 leaves in each case the remainder 2. The sum of digits of x is

Explanation:

LCM of 15,20 and 28 = 420
and on dividing 9999 (greatest 4 digit no.) by 420, quotient comes 23 and reminder 339
Then the largest no. of 4 digit which is divided by 15,20 and 28 should be :-
420×23 = 9660
But here given that in each case reminder is 2
Thus x = 9660+2 = 9662
Sum of each digits = 9+6+6+2 = 23