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What least value which should be added to 1812 to make it divisible by 7, 11 and 14?
12
36
72
154
he LCM of 7, 11 and 14 = 154 Now, 1812/154 = 11.766 ≈ 12 154 x 12 = 1848 The number to be added = 1848 - 1812= 36 Now,If you add 36 to 1812, you get 1848 And 1848 is divisible by 7, 11, and 14 because it is a multiple of 154 which is the LCM of the three numbers So, 36 is the least number which should be added to 1812 to make it divisible by 7 11 and 1
By: MIRZA SADDAM HUSSAIN ProfileResourcesReport error
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