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A and B together can finish a work in 30 days. They worked for it for 20 days and then B left the work. The remaining work was done by A alone in 20 days more. In how many days can A alone finish the work?
48 days
50 days
54 days
60 days
(A + B)’s combined efficiency = 100/30 = (10/3)%. The work done by both in 20 days= 20*(10/3) = (200/3)%. Remaining work = 100 – (200/3) = (100/3)%. If A does (100/3)% of work in 20 days, then A’s one day work = (100/60)%. Hence, A will alone finish the work in = 100/(100/60) = 60 days.
By: MIRZA SADDAM HUSSAIN ProfileResourcesReport error
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