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The product of the two numbers is 1500 and their HCF is 10. The number of such possible pairs is/are:
1
3
4
2
To find the number of possible pairs of numbers that have a product of 1500 and an HCF of 10, consider the following:
- Let the numbers be 10a and 10b, where a and b are coprime integers (since HCF is 10).
- Thus, 10a * 10b = 1500 implies a * b = 15.
- The possible coprime pairs (a, b) from the factors of 15 are (1, 15) and (3, 5).
So, there are 2 pairs of numbers: (10, 150) and (30, 50).
- Option:4 - 2 is the correct answer as there are two possible pairs.
By: Parvesh Mehta ProfileResourcesReport error
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