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There are two inlets A and B connected to a tank. A and B can fill the tank in 32 h and 28 h, respectively. If both the pipes are opened alternately for 1 h, starting with A, then in how much time (in hours, to nearest integer) will the tank be filled?
22
30
36
24
- Pipe A fills the tank in 32 hours. So, A fills 1/32 of the tank in 1 hour.
- Pipe B fills the tank in 28 hours. So, B fills 1/28 of the tank in 1 hour.
- If both pipes are opened alternately for 1h each (A first, then B), in 2 hours, the tank filled = 1/32 + 1/28
- LCM of 32 and 28 is 224.
- 1/32 = 7/224 and 1/28 = 8/224. So, in 2 hours, 7/224 + 8/224 = 15/224 is filled.
- In x pairs of 2 hours (2x hours), (15x/224) is filled.
- To fill the full tank:
15x/224 ˜ 1 ? x ˜ 224/15 ˜ 14.93 pairs (~15 pairs).
- After 15 pairs (30 hours), 15 × 15 = 225/224 (more than full, so it will be filled just before 30 hours).
- So, option:4 - 24 is closest to actual answer (rounded to nearest integer: 29.8 ˜ 30 hours).
- Correct option is 2 – 30 hours.
- Other answers (22, 36, 24) are not matching the calculated time.
By: Parvesh Mehta ProfileResourcesReport error
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