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If m∠C=m∠Z and AC=XZ, then which of the following conditions is necessary for ΔABC and ΔXYZ to be congruent?
AB=AC
BC=YZ
AB=XY
BC=AB
Let’s break it down:
- We know m?C = m?Z and AC = XZ. That means, in ?ABC and ?XYZ, we already have an angle and its adjacent side equal.
- For triangles to be congruent, you need one of the congruence criteria: ASA, SAS, SSS, or AAS.
Let’s look at the options:
- Option 1: AB = AC
This just tells you two sides in one triangle are equal. It doesn't connect triangle ABC to triangle XYZ. No congruence between the two triangles yet.
- Option 2: BC = YZ
Now, you have AC = XZ, BC = YZ, and included angle C = Z. That’s the SAS (side-angle-side) criterion directly between the two triangles.
- Option 3: AB = XY
If AB = XY and still only one angle (C=Z) is common, not enough info for congruence—angles aren’t included between the known sides.
- Option 4: BC = AB
This only tells you two sides of triangle ABC are equal. It says nothing about triangle XYZ, so it doesn’t help for congruence.
So, what this really means is:
Option 2 (BC = YZ) is necessary.
You get two sides and the included angle equal—classic SAS. Radiantly clear.
By: Parvesh Mehta ProfileResourcesReport error
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