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Area of a sector is 1848 m2and the central angle of the sector is 270o . Find the radius of the circle. (Take π = 22/7)
784 m
22 m
21 m
28 m
- The formula for the area of a sector is: \((\theta / 360) \times \pi r^2\), where \(\theta\) is the central angle and \(r\) is the radius.
- Given area of the sector: 1848 m\(^2\) and \(\theta = 270^\circ\).
- Substitute values: \((270 / 360) \times (22/7) \times r^2 = 1848\)
- Simplify: \((3/4) \times (22/7) \times r^2 = 1848\)
- Further simplification: \((11/14) \times r^2 = 1848\)
- Multiply both sides by 14: \(11 \times r^2 = 1848 \times 14\)
- Divide by 11: \(r^2 = 2352\)
- Take the square root: \(r = 28\)
- The correct answer is Option 4: 28 m
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By: Parvesh Mehta ProfileResourcesReport error
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