A policeman follows a thief, who is 1250 m ahead of him. The policeman and the thief run at the speed of 10 km/h and 8 km/h, respectively. The distance (in km) run by the thief before he is nabbed by the policeman is:
This questions was previously asked in
Combined Graduate Level Examination Tier I 2023
Explanation:
- The initial gap between the policeman and the thief is 1250 meters, which equals 1.25 kilometers.
- The relative speed between the policeman and the thief is 10 km/h - 8 km/h = 2 km/h.
- To close the 1.25 km gap, the time taken is distance/speed = 1.25 km / 2 km/h = 0.625 hours.
- In this time, the thief covers a distance of 8 km/h * 0.625 hours = 5 km.
Option 3: 5 is the correct answer.
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By: Parvesh Mehta