The average of 23 numbers is 51 The average of first 12 numbers is 49 and the average of last 12 num...........

Quantitative Aptitude (CGL) Average

The average of 23 numbers is 51. The average of first 12 numbers is 49 and the average of last 12 numbers is 54. If the twelfth

number is removed, then the average of the remaining numbers (correct to two decimal places) is:

This questions was previously asked in

SSC CGL 24th August 2021 Shift-1

53:25

50.45

51.75

52.65

- The problem involves calculating averages and removing one number from a set.

- Given: Average of 23 numbers is 51. Total sum = 23 * 51 = 1173.

- Average of first 12 numbers is 49. Total sum = 12 * 49 = 588.

- Average of last 12 numbers is 54. Total sum = 12 * 54 = 648.

- Adding these, numbers 12 appears twice. Total = 588 + 648 = 1236.

- If twelfth number \( x \) is added twice, \( 1236 - x = 1173 + x \). Solving gives x = 63.

- Removing twelfth number: Remaining sum = 1173 - 63 = 1110.

- Remaining numbers = 22. New average = 1110 / 22 = 50.45.

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