A railway engine passes two bridges of lengths 400 m and 235 m and 100 seconds and 60 seconds respec...........

Quantitative Aptitude (CGL) Time & distance

A railway engine passes two bridges of lengths 400 m and 235 m and 100 seconds and 60 seconds. respectively. Twice the

length of the railway engine (in m) is:

This questions was previously asked in

SSC CGL 18th April 2022 Shift-2

12.5

- The railway engine first passes a 400m bridge in 100 seconds.

- Next, it passes a 235m bridge in 60 seconds.

- Let the length of the engine be "L" meters.

- The speed of the engine when passing bridges is constant.

- For the first bridge: Total distance = Bridge + Engine length = 400 + L.

- Speed = (400 + L) / 100.

- For the second bridge: Total distance = Bridge + Engine length = 235 + L.

- Speed = (235 + L) / 60.

- Setting the two speed equations equal:

\((400 + L) / 100 = (235 + L) / 60\).

- Solving the equation gives L = 12.5 meters.

- Twice the engine's length: \(2 \times 12.5 = 25\) meters.

- Correct Option is: Option:2, 25

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