Ratio of the present age of a motherto that of the daughteris 7 : 1. After 5 years the ratio will become 4 : 1. What is the
difference (in years) in their present ages?
This questions was previously asked in
SSC CGL 16th August 2021 Shift-1
Explanation:
- Let the present age of the mother be \(7x\) and the daughter be \(x\), where \(x\) is a positive integer.
- The current ratio is therefore \(7:1\).
- After 5 years, the mother's age will be \(7x + 5\), and the daughter's age will be \(x + 5\).
- The future ratio is given as \(4:1\).
- Setting up the equation for the future ratio:
\[
\frac{7x + 5}{x + 5} = \frac{4}{1}
\]
- Cross-multiplying, we get:
\[
7x + 5 = 4(x + 5)
\]
- Simplifying, we find:
\[
7x + 5 = 4x + 20 \\
3x = 15 \\
x = 5
\]
- The mother's present age: \(7x = 35\), the daughter's present age: \(x = 5\).
- The difference in their present ages is: \(35 - 5 = 30\).
- Correct Answer: Option:2, 30
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