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The average of 22 numbers is 37.5. The average of first 12 numbers is 40.6 and that of the last 12 numbers is 35.4. If 11th and
12th numbers are excluded, then what is the average of the remaining numbers?
37.8
36.9
37.4
36.4
- Initial Problem: The average of 22 numbers is 37.5, so their total sum is \(22 \times 37.5 = 825\).
- First 12 Numbers: The average is 40.6, making their total sum \(12 \times 40.6 = 487.2\).
- Last 12 Numbers: The average is 35.4, adding up to \(12 \times 35.4 = 424.8\).
- Overlap of 11th and 12th Numbers: Since both sums include these two numbers, we subtract the total once (11th and 12th numbers).
- Sum of 11th and 12th Numbers: Calculating both average sums includes 11th and 12th twice, leading to a sum of 912 (487.2 + 424.8). From this, subtract 825 (total of all 22, counted once) to find the overlap sum, \(912 - 825 = 87\).
- Remaining 20 Numbers: Exclude these two summed to 87, leaving \(825 - 87 = 738\).
- New Average: Divide the remainder by 20, \(738 \div 20 = 36.9\).
Correct Answer: Option 2: 36.9
By: santosh ProfileResourcesReport error
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