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A train is to cover 370 km at a uniform speed. After running 100 km,the train could run at a speed 5 km/h less than its normal
speed due to some technical fault. The train got delayed by 36 minutes. What is the normal speed of the train, in km/h?
48
45
40
50
- The train covers the first 100 km at its normal speed, which we need to determine.
- Let the normal speed be \( x \) km/h.
- Time taken to cover 100 km at normal speed: \( \frac{100}{x} \) hours.
- For the remaining 270 km, it runs at \( (x - 5) \) km/h.
- Time taken for 270 km at reduced speed: \( \frac{270}{x - 5} \) hours.
- Total time taken if there was no delay: \( \frac{370}{x} \) hours.
- Due to delay, it takes 36 minutes more, which is \( \frac{36}{60} = \frac{3}{5} \) hours.
- Hence, the delay equation is:
$$
\frac{100}{x} + \frac{270}{x - 5} = \frac{370}{x} + \frac{3}{5}
- Solving the above, we find \( x = 50 \).
- Option 4: 50 km/h is the correct Answer.
By: santosh ProfileResourcesReport error
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