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A cylindrical vessel of radius 30 cm and height 42 cm is full of water. Its contents are emptied into a rectangular tub of length

75 cm and breadth 44 cm. The height (in cm) to which the water rises in the tub is: (Take $\pi =_{22}^{7}$ )

This questions was previously asked in

SSC CGL 4th March 2020 Shift-2

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Explanation:

Volume of the cylindrical vessel $\pi r^{2}h=_{7}^{22}\times 30^{2}\times 42 = 118800$

If we replace the water from the cylindrical vessel to rectangular tub then volume should be equal of the cylindrical vessel rectangular
tub.
Volume of the cylindrical vessel = Volume of rectangular tub
118800 = length x breadth × height
118800 = 75 x 44 x height
Height = 118800/3300 = 36 cm

By: santosh

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