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What is the remainder when the product of 335, 608 and 853 is divided by 13?
11
12
6
7
Let's solve the problem step by step and find the remainder when the product of 335, 608, and 853 is divided by 13:
- Step 1: Calculate \(335 \mod 13\).
- 335 divided by 13 gives a remainder of 10.
- Step 2: Calculate \(608 \mod 13\).
- 608 divided by 13 gives a remainder of 10.
- Step 3: Calculate \(853 \mod 13\).
- 853 divided by 13 gives a remainder of 8.
- Step 4: Calculate the product of the remainders: \(10 \times 10 \times 8\).
- This gives us 800.
- Step 5: Calculate \(800 \mod 13\).
- 800 divided by 13 gives a remainder of 7.
- Conclusion: The remainder when the product of 335, 608, and 853 is divided by 13 is $$\text{\color{green}7}$$, which corresponds to Option 4.
Your overall understanding seems correct, and your answer is right.
By: santosh ProfileResourcesReport error
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