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What is the greatest number by which when 156. 181 and 331 are divided, the remainder is 6 in each case?
26
17
25
13
To determine the greatest number that leaves a remainder of 6 when 156, 181, and 331 are divided by it, follow these steps:
- Subtract 6 from each number to get dividends:
- 150 from 156
- 175 from 181
- 325 from 331
- Now, find the greatest common divisor (GCD) of 150, 175, and 325.
- Calculate GCD as follows:
- Prime factorization:
- 150 = \(2 \times 3 \times 5^2\)
- 175 = \(5^2 \times 7\)
- 325 = \(5^2 \times 13\)
- The common factor is \(5^2\), which is 25.
- Thus, the greatest number by which the numbers can be divided to leave a remainder of 6 is 25.
- Option 3: 25 is the correct answer.
By: santosh ProfileResourcesReport error
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