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In an isosceles triangle, the length of each equal side is twice the length of the third side. The ratio of areas of the isosceles triangle and an equilateral triangle with same perimeter is
30v5 : 100
32v5 : 100
36v5 : 100
42v5 : 100
h=√((4a)^2−(a)^2) h=√(16a^2−a^2) h=√(15a^2) h=a√15 area=1/2×2a×h =12×2a×a.√15 perimeter of equilateral triangle is =4a+4a+2a=10a each side of triangle =10a/3 area of equilateral triangle =√3/4 * 10/3 * 10/3 * a^2 25√3*a^2/9 area of isosceles?/area of equilateral? =1/2×2a×a√15/25√3a^2/9 =36√5:100
By: MIRZA SADDAM HUSSAIN ProfileResourcesReport error
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