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If a cone is divided into two parts by drawing a plane through the midpoints of its axis, then the ratio of the volume of the 2 parts of the cone is
1 : 2
1 : 4
1 : 7
1 : 8
Let PQ be the plane which passes through middle point O of the axis AO of the cont(A,BC). Let r be the radius of the cone (A, PQ) and h its height. Then, from geometry, radius of the cone (A,BC) is 2r and its height is 2h. Volume of the cone (A, PQ) = (1/3)πr^2h Volume of the cone (A,B,C) = (1/3)πr^2.(2r)^2(2h) = (8/3)πr^2h Volume of the portion (PB, OC) = Volume of the cone (A, BC) - Volume of the cone (A, PQ) = (8/3)πr^2h - (1/3)πr^2h = (7/3)πr^2h Required ratio = ((1/3)πr^2h)/((7/3)πr^2h) = 1/ 7 = 1 : 7
By: MIRZA SADDAM HUSSAIN ProfileResourcesReport error
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