Three runners A B and C run a race with runner A finishing 12 meters ahead of runner B and 18 meters...........

Quantitative Aptitude (CGL) Time & distance

Three runners A,B and C run a race, with runner A finishing 12 meters ahead of runner B and 18 meters ahead of runner C, while runner B finishes 8 meters ahead of runner C. Each runner travels the entire distance at a constant speed. The length of the race is

36 Metres

48 Metres

60 Metres

72 Metres

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Explanation:

Let A finisher the race of x km
Distance travelled by A = x
Distance travelled by B = x – 12
Distance travelled by C = x – 18
in another race B & C
Distance travelled by B = x km
Distance travelled by C = x – 8 km
(x-12)/(x-18)=x/(x-8)
x = 48