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PQRA is a rectangle, AP = 22 cm, PQ = 8 cm. ?ABC is a triangle whose vertices lie on the sides of PQRA such that BQ = 2 cm and QC = 16 cm .Then the length of the line joining the mid points of the sides AB and BC is
4v2 cm
5 cm
6 cm
10 cm
Made a triangle such that B, is on side PQ and BQ = 2 cm And C is on RQ such that QC = 16 cm Because all the vertices are on sides of PQRA. Now, PQRA is a rectangle so all the angle will be of 90° ∠ARQ=90° and RC=RQ−CQ=22−16cm=6cm In right angle ?ARC AC2=AR2+RC2=82+62 AC=10 Now in ?ABC AC is 10 cm and M, N are the mid point of ?ABC So, MN=10/2=5cm
By: MIRZA SADDAM HUSSAIN ProfileResourcesReport error
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